Energy Required
To raise 1 kg of this material by 10 K requires 41860.0 Joules of energy.
Power Output
Delivering this energy over 1 seconds requires a power of 41860.0 Watts.
Material Property
The specific heat capacity (4186 J/kg*K) determines how much energy is stored per degree of temperature change.
How to Use
- 1Enter the mass of the substance being heated or cooled
- 2Input the specific heat capacity of the material
- 3Set the temperature change (final - initial temperature)
- 4Enter the time for power calculations
- 5Set the efficiency for energy calculations
- 6Review the calculated heat transfer and related quantities
Heat Transfer Formula
Q = mc?TVariables:
QHeat transfer (J)mMass (kg)cSpecific heat capacity (J/kg*K)?TTemperature change (K)Example
Inputs:
Steps:
- 1.Calculate heat transfer: Q = mcDeltaT = 1 x 4186 x 10 = 41,860 J
- 2.Calculate power: P = Q/t = 41,860/1 = 41,860 W
- 3.This represents heating 1 kg of water by 10 C
- 4.Water has a high specific heat capacity of 4186 J/kg*K
