Energy State
The particle is in energy state n=1. The energy is 6.02e-18 Joules. Energy increases with n^2 (quadratic).
Wave Properties
The associated de Broglie wavelength is 2.00e-10 meters. It fits 0.5 full waves inside the box.
Probability
At x=5.00e-11 m, the probability density is 1.000. This indicates how likely it is to find the particle at this location.
How to Use
- 1Enter the quantum number (n = 1, 2, 3, ...)
- 2Input the length of the potential well.
- 3Set the position to calculate probability density.
- 4Review the calculated wave function properties.
- 5Use the quantum analysis to understand particle behavior.
Wave Function Formula
psi(x) = sqrt(2/L) sin(npi x/L)Variables:
psi(x)Wave functionnQuantum number (1, 2, 3, ...)LLength of the box (m)xPosition (m)Example
Inputs:
Steps:
- 1.Calculate energy: E = n^2 h^2 / (8mL^2).
- 2.Calculate wavelength: lambda = 2L/n = 2 x 10^-10 m.
- 3.Calculate probability: |psi|^2 = sin^2(pi x/L) = 1 at the center for n = 1.
- 4.This represents the ground state of a particle in a box.
