| AB | Ab | aB | ab | |
|---|---|---|---|---|
| AB | AABB | AABb | AaBB | AaBb |
| Ab | AABb | AAbb | AaBb | Aabb |
| aB | AaBB | AaBb | aaBB | aaBb |
| ab | AaBb | Aabb | aaBb | aabb |
Phenotype Ratios
- Dom A, Dom B:9/16 (56.3%)
- Dom A, Rec B:3/16 (18.8%)
- Rec A, Dom B:3/16 (18.8%)
- Rec A, Rec B:1/16 (6.3%)
Independent Assortment
This cross demonstrates Mendel's law of independent assortment. The two traits segregate independently, producing 16 possible offspring combinations.
Classic Ratio
For AaBb x AaBb, the expected phenotypic ratio is 9:3:3:1 (9 dominant-dominant, 3 dominant-recessive, 3 recessive-dominant, 1 recessive-recessive).
Applications
Dihybrid crosses are fundamental in genetics for predicting offspring traits in breeding programs and understanding genetic linkage.
How to Use
- 1Enter the 4-letter genotype for Parent 1 (e.g., AaBb).
- 2Enter the 4-letter genotype for Parent 2.
- 3View the 4x4 Punnett square and phenotype ratios.
Mendelian Inheritance
9:3:3:1 Phenotypic RatioVariables:
A/aFirst trait allelesB/bSecond trait allelesExample
Inputs:
Steps:
- 1.Gametes: AB, Ab, aB, ab (each parent)
- 2.16 offspring combinations
- 3.Classic 9:3:3:1 ratio expected
